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(3/5)^(x-1)=(25)/(9)
We move all terms to the left:
(3/5)^(x-1)-((25)/(9))=0
Domain of the equation: 5)^(x-1)!=0We add all the numbers together, and all the variables
x∈R
(+3/5)^(x-1)-(+25/9)=0
We get rid of parentheses
(+3/5)^(x-1)-25/9=0
We calculate fractions
()/5^x+(-125x)/5^x=0
We multiply all the terms by the denominator
(-125x)+()=0
We add all the numbers together, and all the variables
(-125x)=0
We get rid of parentheses
-125x=0
x=0/-125
x=0
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